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6n^2+9n-42=0
a = 6; b = 9; c = -42;
Δ = b2-4ac
Δ = 92-4·6·(-42)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-33}{2*6}=\frac{-42}{12} =-3+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+33}{2*6}=\frac{24}{12} =2 $
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